Optimization Calculus?!

Hi I'm resolve the question, but I'm having no luck, the specific question: filter Coffee has the form of an inverted cone. Water flows from the filter at a rate of 10 cm ^ 3/min. When the depth water in the cone is 8cm, the depth is down 2 cm / min. What is the ratio of the height of the cone to its radius? Any help will be greatly appreciated! Thank you very much

Ok see if this is meaningful (it may be far away so just to warn you) Let the ratio, H / R = a. Then, Ar = H and R = h / a = π Volume So r ^ 2 h / 3 = π (h / a) ^ 2 h / 3 = π h ^ 3 / (3a ^ 2) while dV / dh = Π h ^ 2 / a ^ 2 and dv / dt = 10 then dh / dt • DV / DH dh = dV / dt / dt • π h ^ 2 / a ^ 2 = 10 dh / dt = 10 / (π h ^ 2 / a ^ 2) = 10a ^ 2 / (π ^ 2 h) taken at 8 and 2 h dh / Dt 2 = 10a ^ 2 / (64π) to solve for

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